Figure 3 Initializing a population of ten strings
<B>Strings 1s Count Prob.</B> U 1 0 0 0 0 0 0 0 0 0 0 0 0 0 1 10% W 0 0 1 0 0 0 1 0 0 0 0 0 0 0 2 20% X 0 1 1 1 0 0 0 0 0 1 1 0 0 1 6 30% Y 0 0 1 1 0 1 1 0 0 1 1 0 0 0 6 40% X 1 1 0 1 0 1 0 1 1 0 1 1 0 0 8 50% String's complement ~U 0 1 1 1 1 1 1 1 1 1 1 1 1 1 ~W 1 1 0 1 1 1 0 1 1 1 1 1 1 1 ~X 1 0 0 0 1 1 1 1 1 0 0 1 1 0 ~Y 1 1 0 0 1 0 0 1 1 0 0 1 1 1 ~X 0 0 1 0 1 0 1 0 0 1 0 0 1 1